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1 1 1

0 1 2

Figure 12.23 Four possible outcomes after treatment of DNA with an alkylating agent, which removes the

1 0 0x0FF( 1)

purine adenine in this example. The bases shown in red are the four bases that DNA polymerase may insert opposite the gap. After another round of DNA replication, the gap remains to generate further mutations. The inserted base forms a base pair (blue), which can be a restoration or a transition or transversion mutation.

1 1 0

=LEFT('Products'[QuantityPerUnit],1)

The McGraw Hill Companies, 2001

0 1 0

the DC ag becomes dif cult to work with, and speci c examples for its use (such as the ASCII-to-nybble conversion routines) have to be designed. When you are rst learning how to program in assembly language, you may want to convert high level language statements into assembly language using formulas or basic guides. When you look at subtraction for comparing, the code seems very complex. In actuality, using the PIC microcontroller subtract instruction isn t that complex, and the instruction sequence

code was read from a xed point and that it was triplet (chapter 11).

is required, where Cond is one of the values speci ed in Table 8.2. By selecting a STATUS ag (carry on zero) to test, the execution of the goto instruction can be speci ed, providing you with a simple way of implementing the conditional jumps using the code listed in Table 8.3.

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Additions and deletions in DNA can also come about by misalignment of a template strand and the newly formed (progeny) strand in a region containing a repeated se-

Jump if equal Jump if not equal Jump if FIRST is greater than the second Jump if FIRST is greater than or equal to the second Jump if FIRST is less than the second Jump if FIRST is less than or equal to the second

11

quence. For example, in gure 12.25 we expect the progeny strand to contain six adjacent adenines because the template strand contains six adjacent thymines. Misalignment of the progeny strand results in seven consecutive adenines: six thymines replicated, plus one already replicated but misaligned. Misalignment of the template strand results in ve consecutive adenines because one thymine is not available in the template. Regions with long runs of a particular base may be very mutation prone. They may explain the hot spots observed by Benzer (see g. 12.8) and others.

movf A, w/movlw A subwf B, w/sublw B btfsc STATUS, Z goto Label ; Jump if Z = 1 movf A, w/movlw A subwf B, w/sublw B btfss STATUS, Z goto Label ; Jump if Z = 0 movf B, w/movlw A subwf B, w/sublw B btfss STATUS, C goto Label ; Jump if C = 0 movf B, w/movlw B subwf A, w/sublw B btfsc STATUS, C goto Label ; Jump if C = 1 movf B, w/movlw B subwf A, w/sublw A btfss STATUS, C goto Label ; Jump if C = 0 movf A, w/movlw A subwf B, w/movlw B btfsc STATUS, C goto Label ; Jump if C = 1

A B != 0

When a critical mutation occurs in a codon, several routes can still lead to survival of the individual; simple reversion and intragenic suppression are two that we have already considered. A third route is through intergenic suppression restoration of the function of a mutated gene by changes in a different gene, called a suppressor gene. Suppressor genes are usually transfer RNA genes. When mutated, intergenic suppressors change the way in which a codon is read. Suppressor genes can restore proper reading to nonsense, missense, and frameshift mutations. Nonsense mutations convert a codon that originally speci ed an amino acid into one of the three nonsense

This is a useful table to remember when you are working on PIC applications, even if you aren t simply converting high level language source code by hand into PIC microcontroller assembly. Negation of the contents of a le register is accomplished by performing the two s complement operation. By de nition, this is done by inverting the contents of a register and then incrementing:

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